A very widespread mistake is to believe that an increase of p%p\% followed by a decrease of p%p\% brings you back to the starting value. This is not so, and the reason is purely algebraic: the two changes are applied to different bases.

Caution

An increase of p%p\% followed by a decrease of p%p\% (or vice versa) does not bring you back to the initial value! 100+p100100p100=10000p210000<1for every p>0.\frac{100+p}{100}\cdot\frac{100-p}{100} = \frac{10000-p^2}{10000} < 1 \quad\text{for every }p>0.

The product of the two factors equals 10000p210000\frac{10000-p^2}{10000}, which is strictly less than 11 for every p>0p>0: the final value is therefore always lower than the initial one. It is the same asymmetry that we shall find again when comparing VAT added and VAT extracted.

Topics: Percentages
Concepts: Percentage increase · Percentage decrease · Percentage change
Skills: Calculating · Proving