Example — Lottery, winning five-number combination

What is the probability of guessing a five-number combination at the lottery, choosing 55 numbers out of 9090?

The total cases are the simple combinations of 9090 taken 55 at a time (order does not matter):

(905)=90898887865!=43949268.\binom{90}{5} = \frac{90\cdot 89\cdot 88\cdot 87\cdot 86}{5!} = 43\,949\,268.

The favourable cases are 11 (the winning five-number combination). So

P=1439492682,3108,P = \frac{1}{43\,949\,268} \approx 2,3\cdot 10^{-8},

roughly one chance in 4444 million.

Topics: Probability
Concepts: Simple combinations · Probability
Methods: Simple combinations
Skills: Combinatorics · Probability calculation