In a right-angled triangle the trigonometric functions take on an immediate meaning: they are simple ratios between the sides. This is the starting point for solving any triangle.
Property — Relations in right-angled triangles
Let be a right-angled triangle with the right angle at , legs , , hypotenuse , angle opposite the leg , angle opposite the leg . Then:
\sin\alpha &= \frac{\text{cateto opposto ad }\alpha}{\text{ipotenusa}} = \frac{a}{c}, & \cos\alpha &= \frac{\text{cateto adiacente ad }\alpha}{\text{ipotenusa}} = \frac{b}{c}, \\ \tan\alpha &= \frac{\text{cateto opposto}}{\text{cateto adiacente}} = \frac{a}{b}. \end{aligned}$$ With analogous formulae for $\beta$, swapping the roles of $a$ and $b$.
These formulae generalise the definition of , , given on the trigonometric circle: the right-angled triangle with vertices , and the projection of onto the -axis has hypotenuse (the radius), and its legs are (horizontal) and (vertical).
Links
Topics: Triangle trigonometry
Concepts: Triangle solving · Right-angled triangle
Functions: Cosine · Sine · Tangent
Skills: Synthetic geometry · Using formulae