Let us see the sum-product method at work on a fractional and symmetric system.

Example

{1x+1y=1235xy+yx=7435Existence conditions: x0,y0.\begin{cases} \dfrac{1}{x}+\dfrac{1}{y}=\dfrac{12}{35} \\[6pt] \dfrac{x}{y}+\dfrac{y}{x}=\dfrac{74}{35} \end{cases} \qquad\text{Existence conditions: } x\neq 0,\, y\neq 0. The first equation gives SP=1235\dfrac{S}{P}=\dfrac{12}{35}; the second S22PP=7435\dfrac{S^2-2P}{P}=\dfrac{74}{35}.

From the first: P=35S12P=\dfrac{35S}{12}. Substituting into the second: 35S2144P=0    35S214435S12=0    35S(S12)=0.35S^2 - 144P = 0 \implies 35S^2-144\cdot\frac{35S}{12}=0 \implies 35S(S-12)=0. S=0S=0 is not acceptable (existence conditions), hence S=12S=12, P=35P=35. t212t+35=0    (t7)(t5)=0    (x,y)=(7,5) or (5,7)t^2-12t+35=0 \implies (t-7)(t-5)=0 \implies \boxed{(x,y)=(7,5) \text{ or } (5,7)}

Topics: Second-degree equations
Concepts: Symmetric system · Sum and product of the roots
Methods: Sum and product of the roots
Skills: Solving systems