Let us see how a discussion is carried out in practice, distinguishing all the cases that the parameters can generate.

Example

Solve a2x+axab=0a^2x + ax - ab = 0 as a,bRa,b\in\mathbb{R} vary.

We collect the xx: x(a2+a)=abx(a^2+a) = ab, that is xa(a+1)=abx\cdot a(a+1) = ab.

Discussion:

  • If a0a\neq 0 and a1a\neq -1: the coefficient a(a+1)0a(a+1)\neq 0, hence x=aba(a+1)=ba+1(unique solution)x = \frac{ab}{a(a+1)} = \boxed{\dfrac{b}{a+1}} \quad\text{(unique solution)}
  • If a=0a = 0: the equation becomes 0=00 = 0, always true     \implies indeterminate (infinitely many solutions).
  • If a=1a = -1: the equation becomes 0=b0 = -b, and we must distinguish further:
    • if b=0b=0: 0=0    0=0 \implies indeterminate;
    • if b0b\neq 0: 0=b0    0 = -b \neq 0 \implies impossible (no solution).

The example shows the general logic: we isolate the coefficient of the unknown, set it to zero to find the “critical” values of the parameters and analyse each of them separately.

Topics: First-degree equations
Concepts: Parametric discussion · Impossible equation · Indeterminate equation · Literal equation · Parameter
Skills: Reasoning by cases · Solving equations